APSSB/SSC CGL/SSC GD TEST

                             MCQ TEST

Question 1: If a number is as much greater than 31 as it is less than 75, then the number is :?

A) 53

B) 103

C) 74

D) 76

Explanation:let the number be x Then, x-31=75-x 2x=75+31=106 x=106/2 x=53 .

Question 2: A is thrice as efficient as B. A takes 24 days less than B to complete a work. If they work together, in how many days, will the work be completed?

A) 12

B) 8

C) 15

D) 9

Explanation:Ans : (B) 9 A : B Working capacity 3 : 1 Time 1 : 3 2 = 24 1 = 12 A 12 3 36 B 36 1 36 A+B=\frac{36}{4}=9 day.

Question 3: A can do 60% of a work in 18 days, while B can do 40% of the same work in 10 days. Both work together for 10 days only, C completed the remaining work in 4 days. In how many days will C complete the same work? ?

A) 15

B)25

C)18

D)12

Explanation: Ans : (A) 15 A x 60% = 18 A\times\frac35=18 A = 30 days B x 40% = 10 B\times\frac25=10 B = 25 days A = 30 B = 25 TW = 150 A 30 5 150 B 25 6 150 (A+B) x 10 = (6+5) x 10 = 110 work left work = 150 – 110 = 40 working capacity of C =\frac{40}{4}=10 C alone total work =\frac{150}{10}=15 days.

Question 4:The LCM of two numbers is 2079 and their HCF is 27. If one of the numbers is 189, the other number is

A)297

B)584

C)189

D)216

Explanation:HCF x LCM = First number x Second number 2079 x 27 = 189 x Second number Second number = 297

Question 5: The product of two co-prime numbers is 117. Then their LCM is?

A)117

B)9

C)13

D)39

Explanation:HCF of two Co-prime numbers are always 1 HCF x LCM = First number x Second number =117 1 x LCM = 117

Question 6:The LCM of three different numbers is 120. Which of the following cannot be their HCF? ?

A) 8

B) 12

C)24

D)35

Explanation:120 = 2x2x2x3x5 Possible value of HCF are 4,8,12,24 Hence 35 can not be HCF.

Question 7:The LCM of two numbers is 864 and their HCF is 144. If one of the number is 288, then the other number is ?

A) 576

B)1296

C)432

D)144

Explanation:First number x Second number =HCF x LCM 288 x S = 864 x 144 S = 432.

Question 8:Find the least number which when divided separately by 15, 20, 36 and 48 leaves 3 as remainder in each case.

A) 183

B) 243

C) 483

D) 723

Explanation:LCM of 15,20,36, 48 is 2x2x3x5x3x4 = 720 Required number is 720 +3 = 723.

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Question 9:The greatest 4-digit number exactly divisible by 10, 15, 201 is

A) 9990

B)9960

C)9980

D)9995

Explanation:LCM of 10,15,20 is 60 Divide largest 4 digit number 9999 by 60 and remainder is 39 Hence required number is 9999 - 39 =9960.

Question 10:The smallest number, which, when divided by 12 or 10 or 8, leaves remainder 6 in each case, is

A)246

B)186

C)126

D)66

Explanation:LCM = 120 Required number is 120 +6 = 126.

Question 11: A man walking at the rate of 5 km/hr. crosses a bridge in 15 minutes. The length of the bridge (in metres) is : ?

A) 600

B)750

C)1000

D)1250

Explanation:1250 m Speed of the man = 5km/hr = 5 x \dfrac{1000}{60} = latex \dfrac{250}{3} m / min Time taken to cross the bridge = 15 minutes Length of the bridge = speed × time = \dfrac{250}{3} x15 m =1250 m.

Question 12:A train is moving with the speed of 180 km/hr. Its speed (in metres per second) is :

A)5

B)40

C)30

D)50

Explanation:50 \dfrac{180x 5}{18} m/sec = 50 m/sec.

Question 13:A speed of 30.6 km/.hr is the same as ?

A)8.5 m/sec

B)10.5 m/sec

C) 12.5 m/sec

D)15.5 m/sec

Explanation:30.6 kmph = 30.6 x \dfrac{5}{18} =8.5 m/sec.

Question 14: A car travels at a speed of 60 km/hr and covers a particular distance in one hour. How long will it take for another car to cover the same distance at 40 km/hr ?

A) \dfrac{5}{2} hours

B)2 hours

C) \dfrac{3}{2} hours

D)1 hour

Explanation:Distance = Speed × Time= 60 km. Time taken at 40 kmph = \dfrac{60}{40} = \dfrac{3}{2} hours.

Question 15:Gautam goes to office at a speed of 12 kmph and returns home at 10 kmph. His average speed is : ?

A)11 kmph

B)22 kmph

C)10.9 kmph

D)12.5 kmph

Explanation:Here distances are same. Average speed = \dfrac{2xy}{x+y} kmph =\dfrac{2x12x10}{12+10} =\dfrac{240}{22} kmph.

Question 16:If x % of y % of 80 is the same as 25% of 900, then the value of xy is : ?

A)30100

B)32500

C)28125

D)34200

Explanation:80\times \frac {y}{100} \times \frac{x}{100} = \frac{900 \times 25}{100} \frac {xy \times 80}{10000} = 9 \times 25 =>xy = \frac {9 \times 25 \times 10000}{80} =28125.

Question 17: If 8% of x = 4% of y, then 20% of x is : ?

A)10% of y

B)16% of y

C)14% of y

D)80% of y

Explanation:x \times \frac {8}{100} = y \times \frac {4}{100} x= \frac y2 20% of x is = \frac {20}{100} \text { of } \frac y2 => \frac{10}{100} \text{ of } y= 10% of y.

Question 18: When 75 is added to 75% of a number, the answer is the number itself. Find 40% of that number :

A)80

B)60

C)120

D)160

Explanation:x \times \frac {75}{100} + 75 = x => x - \frac {3x}{4} = 75 => \frac x4 =75, x=300 40% of 300 = \frac {300 \times 40}{100} =120.

Question 19: In a village 30% of the population is literate. If the total population of the village is 6600, then the number of illiterate : ?

A)1980

B)4620

C)2200

D)3280

Explanation: \frac {6600 \times 70}{100} = 4620.

Question 20:A box has 100 blue balls, 50 red balls, 50 black balls. 25% of blue balls and 50% of red balls are taken away. The percentage of black balls at present is :

A)34\frac13%

B)33\frac13%

C)31\frac13%

D)32\frac13%

Explanation:After taking away respective balls, remaining balls are = 75+25+50=150 Percentage of black balls = \frac {50}{150} \times 100 = 33\frac13%.

Question 21: The population of a village is 25,000. One fifth are females and the rest are males. 5% of males and 40% of females are uneducated. What percentage of the whole are educated?

A)78%

B)89%

C)98%

D)88%

Explanation:Female one fifth = 5,000, Male = 25,000 -5,000 = 20000 Educated male = 95% of 20000 =19000 Educated Female = 60%of 5000 =3000 Total educated person = 22000 Required % \frac {22000}{25000} \times100=88%.

Question 22: A team played 40 games in a season and won in 24 of them. In what per cent of games played did the team win?

A) 60%

B) 63%

C) 68%

D) 65%

Explanation:\frac {24}{40} \times 100 = 60%.

Question 23: If 20% of A = 50% of B, then what per cent of A is B?

A)40%

B)30%

C)44%

D)34%

Explanation:20% of A = 50%B => 2A = 5B => A = \frac {5B}{2} Let B is x% of A \frac {5B}{2} \times \frac{x}{100} = B => x = 40%.

Question24:Nongman donated 3% of his income to a charity and deposited 12% of the rest in bank. If now he has ₹ 12804, then his income was : ?

A) ₹ 17460

B) ₹ 18500

C) ₹ 14500

D) ₹ 15000

Explanation:Let Nongman salary ₹ A Remaining after Donation \frac {97A}{100} Remaining after deposit in bank \frac{97A}{100} \times \frac {88}{100} = 12804 => A = \frac{12804 \times 10000}{97 \times 88} = 15000. weise bata du Nongman mera dost hai:-)

Question25:Mungdan spends 75% of his income. His income is increased by 20% and he increased his expenditure by 10%. His savings is increased by :

A)50%

B)45%

C)30%

D)40%

Explanation:Income =100, Expenditure = 75, Saving 25 New Income = 120, New Expenditure \frac {75 \times 110}{100} = 82.5 New Saving = (120 – 82.5) = 37.5 Increase in saving = 37.5 – 25 = 12.5 % increase = \frac {12.5 \times 100}{25} = 50%.

Question26: Jawkhum saves 14% of his salary while Shyam saves 22%. If both get the same salary and Shyam saves ₹ 1540, what is the savings of Jawkhum?

A)680

B)780

C)880

D)980

Explanation:Let Ram and Shyam salary is ₹A \frac {22 \times A}{100} =1540 A= \frac{1540 \times 100}{22} = 7000 Ram Saving = \frac {14 \times 7000}{100} =980.

Question 27: michael’s salary is 20% more than that of Thuming. If michael saves ₹ 720 which is 4% of his salary, then thuming’s salary is :

A)18000

B)17000

C)16000

D)15000

Explanation:Let michael salary = A \frac {A \times 4}{100} = 720 A = 18000 thuming Salary \frac {100}{120} \times 18000 = 15000.

Question 28:Mongnu gets 20% marks in an examination, fails by 30 marks. But if he gets 32% marks, he gets 42 marks more than the minimum pass marks. Find the pass percentage of marks.

A)27%

B)25%

C)26%

D)33%

Explanation:Let Maximum (full) marks is x. \frac {x \times 32}{100} - \frac{x \times 20}{100} = 30+42 => x =600 Minimum passing marks = \frac{600 \times 20}{100} + 30 = 120+30 =150 Pass percentage of marks = \frac{150}{600} \times 100 = 25%.

Question 29: At an election there were two candidates Krishna and Nongman. krishna got 38% of votes and lost by 7200 number of votes. The total number of valid votes were :

A)20000

B)25000

C)30000

D)28000

Explanation:Let valid vote = x (62 – 38)% of x = 7200 => x \times \frac {24}{100} = 7200 => x = 30000.

Question 30:There are 8 houses in a line and in each house only one boy lives with the conditions as given below: 1.Singlik is not the neighbour of Simran. 2.Acho is just next to the left of Thuming. 3.There is at least one to the left of Thuming. 4.Pinki lives in one of the two houses in the middle. 5.Mickael lives in between Pinki and Thuming. 6.If at least one lives to the right of Galmu and Acho is not between Arshi and Thuming, then which one of the following statement is not correct ? ?

A)Galmu is not at the left end.

B)Galmu is in between Simran and Arshi.

C)Arshi is in between Pinki and Singlik.

D)There are three persons to the right of Pinki

Explanation:Khud Samajh Lo.

Question 31:Which number should come next in the series, 48, 24, 12, ......?

A)8

B)6

C)4

D)2

Explanation:It is a simple division series in which each number is one-half of the previous number. We can also say that each number is divided by 2 to arrive at the next number; On dividing 48 by 2, we get 24 On dividing 24 by 2, we get 12 So, on dividing 12 by 2, we will get 6 (option B)..

Question 32: RQP, ONM, _, IHG, FED, find the missing letters. ?

A)LKJ

B)LKI

C)LKM

D)LKN

Explanation:The series consists of letters in reverse alphabetical order. Therefore, the missing letters are LKJ..

Question 33: PETAL: FLOWER ?

A)Engine: Car

B)Cat: Dog

C)PEN:PENCIL

D)KRISHNA:SINGLE

Explanation:.

Question 34:Which word does not belong to others? ?

A)INCH

B)KG

C)CM

D)YARD

Explanation:A kilogram measures weight and the other units are used to measure length..

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